Hello! Welcome to our next lesson on thermodynamics.
In our last session, we established the Principle of Increasing Entropy, which provides a definitive test for whether a process is possible (). We saw that to apply this principle, we need to calculate the entropy change of the system ().
Today's lesson focuses on exactly that. Our goal is to calculate entropy changes for ideal gases undergoing various thermodynamic processes. Air, the working fluid in many aerospace applications, is often modeled as an ideal gas. Mastering these calculations is therefore essential for analyzing components like compressors, turbines, and nozzles in a jet engine. We'll develop the core equations you'll use throughout the rest of this course.
1. The Foundation: T-ds Relations
To find the change in entropy, we need to relate it to other properties we can measure, like temperature, pressure, and volume. The starting points for these relationships are the two Gibbs equations, also known as the T-ds relations. For an internally reversible process, they are:
Here, is specific entropy, is specific internal energy, is specific enthalpy, is temperature, is pressure, and is specific volume.
For an ideal gas, we know that , , and from the ideal gas law, . By substituting these into the Gibbs equations and rearranging, we can get expressions for the change in entropy, .
The following image from NASA provides a clear, step-by-step derivation of the final integrated formulas we'll be using. It's a great visual summary that aligns with your preference for formula-based approaches.

As the derivation shows, we arrive at two main equations for the change in specific entropy, :
The main challenge is how to handle the integrals involving specific heats, and , which are dependent on temperature. This leads to two common methods.
2. Two Methods for Calculating Entropy Change
There are two primary approaches to solving these equations, depending on the required accuracy and the magnitude of the temperature change.
Entropy Change of Ideal Gases | Thermodynamics | (Solved Examples)
This video provides an excellent introduction to the two methods we'll be discussing. It clearly lays out the formulas for each.
Watch the first 2 minutes and 20 seconds (00:00 - 02:20). The presenter introduces the 'constant specific heats' (approximate) method and the 'variable specific heats' (exact) method and presents the key formulas for each.
Method 1: Approximate Analysis (Assuming Constant Specific Heats)
For processes where the temperature range is not too large (e.g., a few hundred Kelvin), we can simplify the calculation by assuming the specific heats and are constant. We typically use an average value for the given temperature range.
With this assumption, and come out of the integral, and . The entropy change equations become:
This method is computationally simpler but less accurate, especially for the large temperature changes seen in gas turbines.
Method 2: Exact Analysis (Using Variable Specific Heats)
For higher accuracy, especially in aerospace applications, we must account for the fact that specific heats change with temperature. To avoid performing the complex integral every time, thermodynamicists have pre-calculated its value and tabulated it.
We define a new property called standard entropy, denoted as , which is a function of temperature only:
The value of at various temperatures can be found in ideal gas property tables (e.g., for air).
Using this, the entropy change is the difference in these tabulated values plus the pressure term:
This is the exact method because it correctly accounts for the variation of specific heat with temperature.
Entropic State Eqns. – Ideal Gases
These lecture notes from Georgia Tech's School of Aerospace Engineering provide a concise, graduate-level summary of these relationships. They are highly relevant to your goals.
Please review the first four pages of this document. It quickly derives the same equations we've discussed, introduces the standard entropy function s°(T), and presents the final formulas for both the CPG (Constant Pressure Gas, our 'approximate' method) and non-CPG ('exact' method) cases.
3. Special Case: Isentropic Processes ()
A process that is both adiabatic (no heat transfer) and reversible (no friction or other losses) has zero entropy change. This is called an isentropic process (). This is an important idealization for components like compressors and turbines in a jet engine.
By setting in our previous equations, we can derive special relationships between properties for an isentropic process.
Using Constant Specific Heats
If we set in the approximate formula, we get:
Using the relationships and , this can be rearranged into the famous isentropic relations:
These are powerful, quick-use formulas for analyzing ideal processes.
Using Variable Specific Heats (Exact Analysis)
For a more accurate isentropic analysis, we set in the exact equation:
To make this easier to use, we define two new properties, relative pressure () and relative volume (), which are also functions of temperature and are tabulated for ideal gases. They are defined such that for an isentropic process:
This method allows for a highly accurate analysis of isentropic processes by simply looking up values in a table, avoiding the less accurate constant specific heat assumption.
Entropic State Eqns. – Ideal Gases
Let's return to the Georgia Tech notes, which cover these isentropic relations perfectly.
Read pages 9 and 10, under the heading 'Isentropic Relations'. The notes derive both the CPG (constant specific heat) relations and the more accurate relations using relative pressure (pr).
4. Putting It All Together: Worked Examples
The best way to solidify these concepts is to see them applied. The following video examples demonstrate how to solve problems using the formulas we've just discussed.
Entropy Change of Ideal Gases | Thermodynamics | (Solved Examples)
The same video from earlier contains a series of excellent, clear examples. Please watch the following segments, paying attention to which formula is chosen for each situation.
Please watch these three distinct examples: Isentropic Compression (07:10 - 08:22): This shows a direct application of the isentropic relations with a constant specific heat assumption. Constant Volume Process (08:22 - 10:06): This shows how the general entropy equation simplifies when volume is constant and how to use the ideal gas law to find missing information. Adiabatic Expansion (10:06 - 12:12): This is a more involved problem requiring an energy balance to find the final temperature before calculating the entropy change.
These examples show the versatility of the entropy change equations. You select the appropriate formula based on the information you have (T, P, v), and you decide whether to use the approximate or exact method based on the required accuracy.
Test your understanding!
Air is compressed in a jet engine from an initial state of kPa and K to a final pressure of kPa. Assuming the process is isentropic and using the constant specific heat assumption, find the final temperature .
For air, you can use .
Show answer
Since the process is isentropic and we are assuming constant specific heats, we can use the isentropic relation linking temperature and pressure:
First, let's calculate the exponent:
Now, substitute the known values into the equation:
Finally, solve for :
The final temperature after compression is approximately 614.4 K.
Conclusion
In this lesson, you have learned the essential methods for calculating entropy changes in ideal gases, a critical skill for analyzing thermodynamic cycles.
Key Takeaways:
- There are two main formulas for calculating entropy change in an ideal gas, one relating (T, v) and the other relating (T, P).
- Approximate Analysis (Constant Specific Heats): A simpler method suitable for small temperature changes, using the familiar isentropic relations with the specific heat ratio .
- Exact Analysis (Variable Specific Heats): A more accurate method crucial for high-temperature applications. It uses the tabulated standard entropy () for general processes and relative pressure () for isentropic processes.
- An isentropic process () is a key idealization for components like turbines and compressors, and we have specific, simplified relations to analyze them.
Preview of the Next Lesson:
Now that we can calculate entropy change, we are ready to analyze entire thermodynamic cycles. In the next lesson, we will analyze the Carnot cycle. The Carnot cycle represents the most efficient possible cycle that can operate between two temperature reservoirs, serving as the ultimate benchmark against which all real heat engines, including jet engines, are measured.
Can't find a good explanation? Sign up and we'll make it for you
Sign up